х = 0
(0<3)v(0>3) = 1 + 0 = 1
x = 2
(2<3)v(2>3) = 1 + 0 = 1
x = 4
(4<3)v(4>3) = 0 + 1 = 1
х = 5
(5<3)v(5>3) = 0 + 1 = 1
х = 0
(0<3)v(0>3) = 1 + 0 = 1
2 случай:x = 2
(2<3)v(2>3) = 1 + 0 = 1
3 случай:x = 4
(4<3)v(4>3) = 0 + 1 = 1
4 случай:х = 5
(5<3)v(5>3) = 0 + 1 = 1