Решить систему уравнений x/2+y/3=6 2x/3-y/3=1 - вопрос №57386392362331 от Perestroika 07.07.2020 23:01

Question

Алгебра: Решить систему уравнений x/2+y/3=6 2x/3-y/3=1

Perestroika · Answer

1/2x+y/3=62x/3-y/3=11/2x×1/3y=62x/3-y/3=16×1/2x+6×1/3y=6×62x/3-y/3=13×x+6×1/3y=6×62x/3-y/3=13×x+2×y=6×62x/3-y/3=13x+2y=362x/3-y/3=12y+4x=362/3x-y/32y+3x=363×2/3×-3×1/3y=32y+3x=362x-3×1/3y=32y+3x=362x-y=3(3+4)x=36+2×3-y+2x=37x=36+2×3-y+2x=37x=36+6-y+2x=37x=42-y+2x=3x=6-y+2x=3x=6-y+12=3x=6-y=3-12x=6-y=-9x=6y=9...