1) f(x)=x^2-10x+16f'(x) = 2x - 10 = 0x = 10/2 = 5f(5)=25-50+16= -9точка минимума (5;-9)log1/5(x/2-3)x/2-3 > 0x/2 > 3x > 6x ∈ (6;+∞)
1) f(x)=x^2-10x+16
f'(x) = 2x - 10 = 0
x = 10/2 = 5
f(5)=25-50+16= -9
точка минимума (5;-9)
log1/5(x/2-3)
x/2-3 > 0
x/2 > 3
x > 6
x ∈ (6;+∞)