given:
γ = 3
τ1 = 3 min 20 s
t1 = 500С
t2 = 300С
find:
τ2 -?
Solution:
〖〖υ₂=υ₁〗^γ〗^((t₂-t₁)/10),(υ₂)/(υ₁)=γ^(Δt/10)
τ inversely proportionalt0 С
〖1) γ〗^(Δt/10) =3^((50-30)/10) =3²=9
In 9 times the rate of reaction will decrease as the temperature decreases from 500C to 300C
2) Time of course of the reaction at lower temperatures will increase by
9 times :200 sec • 9 = 1800 sec = 30 минут - за столько времени закончится эта реакция при понижении температуры с 500С до 300С.
Answer: at a temperature of 300 ° C for 30min the reaction stops.
γ = 3
τ1 = 3 min 20 s
t1 = 500С
t2 = 300С
find:
τ2 -?
Solution:
〖〖υ₂=υ₁〗^γ〗^((t₂-t₁)/10),(υ₂)/(υ₁)=γ^(Δt/10)
τ inversely proportionalt0 С
〖1) γ〗^(Δt/10) =3^((50-30)/10) =3²=9
In 9 times the rate of reaction will decrease as the temperature decreases from 500C to 300C
2) Time of course of the reaction at lower temperatures will increase by
9 times :200 sec • 9 = 1800 sec = 30 минут - за столько времени закончится эта реакция при понижении температуры с 500С до 300С.
Answer: at a temperature of 300 ° C for 30min the reaction stops.