2x²-5x-3=0 3x²+16x-12=0 4x²+8a-32=0 - вопрос №9251830253031612048320 от fhehneeggbvfs 21.08.2021 21:47

Question

Алгебра: 2x²-5x-3=0 3x²+16x-12=0 4x²+8a-32=0

fhehneeggbvfs · Answer

V-квадратный корень 2x²-5x-3=0D=(-(-5))^2-4×2×(-3)=25-(-24)=25+24=49x1=(-(-5)-V49)/2×2=(5-7)/4=-2/4=-1/2x2=(-(-5)+V49)/2×2=(5+7)/4=12/4=33x²+16x-12=0D=(-16)^2-4×3×(-12)=256-(-144)=256+144=400x1=(-16-V400)/2×3=(-16-20)/6=-36/6=-6x2=(-16+V400)/2×6=(-16+20)/6=4/6=2/34x²+8a-32=04x^2=32-8a 4x^2=4(8-2a)|:4x^2=(8-2a)x1=-V(8-2a)x2=V(8-2a)...