131/32*3 1/5-(8 5/9*6/35+22/15)*5/12 - вопрос №7862631131323158596352215512 от александр199110 20.03.2020 16:29

Question

Алгебра: 131/32*3 1/5-(8 5/9*6/35+22/15)*5/12

александр199110 · Answer

1)8 5/9 × 6/35 = 77/9 × 6/35 = 22/15 = 1 7/15
2)1 7/15 + 22/15 = 22/15 + 22/15 = 44/15 = 2 14/15
3)1 31/32 × 3 1/5 = 63/32 × 16/5 = 63/10 = 6 3/10
4)2 14/15 × 5/12 = 44/15 × 5/12 = 11/9 = 1 2/9
5)6 3/10 - 1 2/9 = 63/10 - 11/9 =(63 × 9 - 11 × 10)/90 = 567/90 - 110/90 = 457/90 = 5 7/90
ответ: 5 7/90