(1/6+0,1+1/15): (1/6+0,1-1/15)*2,52/(0,5-1/3+0,25-1/5): - вопрос №77216551601115160111525205130251502516713 от Petrosyaniha 14.07.2021 13:17

Question

Алгебра: (1/6+0,1+1/15): (1/6+0,1-1/15)*2,52/(0,5-1/3+0,25-1/5): (0,25-1/6)*7/13

Petrosyaniha · Answer

(1/6+0,1+1/15):(1/6+0,1-1/15)*2,52/((0,5-1/3+0,25-1/5):(0,25-1/6)*7/13) = 3

1) 1/6 + 0,1 = 10/60 + 6/60 = 16/60 = 4/15
2) 4/15 + 1/15 = 5/15 = 1/3
3) 4/15 - 1/15 = 3/15 = 1/5
4) 1/3 : 1/5 = 5/3
5) 5/3 * 2,52 = 5/3 * 252/100 = 84/20 = 4,2
6) 0,5 + 0,25 = 0,75
7) 0,75 - 1/5 = 0,75 - 0,2 = 0,55
8) 0,55 - 1/3 = 165/300 - 100/300 = 65/300 = 13/60
9) 0,25 - 1/6 = 3/12 - 2/12 = 1/12
10) 13/60 : 1/12 = 13/60 * 12 = 13/5
11)13/5 * 7/13 = 7/5 = 1,4
12) 4,2 : 1,4 = 3