Решить 1. (7а-2,8)×(4.9+3,5а)=0 2. (-2а+6,6)×(4,2а-8,4)=0 - вопрос №7332780172849350226642840 от coolgirl2007 27.08.2020 12:01

Question

Алгебра: Решить 1. (7а-2,8)×(4.9+3,5а)=0 2. (-2а+6,6)×(4,2а-8,4)=0

coolgirl2007 · Answer

1. (7a - 2,8) * (4.9 + 3,5a) = 0 7a - 2.8 = 04.9 + 3.5a = 0a = 2.8/7a = -4.9/3.5a = 0.4a = -1.42. (-2a + 6,6) * (4,2a - 8,4) = 0-2a + 6.6 = 04.2a - 8.4 = 0a = 6.6/2a = 8.4/4.2a = 3.3a = 2...