1)cos x = -(√3/2) 2)sin x =√2/2 3)cos3x = √3/2 - вопрос №669726213222233324232522 от prestigpad 21.01.2022 13:53

Question

Алгебра: 1)cos x = -(√3/2) 2)sin x =√2/2 3)cos3x = √3/2 4)cos(x/2)= √3/2 5) sin(x/2)=√2/2 6)sin3x=√2/2 7)sin(x/3)=-√2

prestigpad · Answer

1x=+-5π/6+2πn,n∈z2x=(-1)^n*π/4+πn,n∈z33x=+-π/6+2πnx=+-π/18+2πn/34x/2=+-π/6+2πnx=+-π/3+πn,n∈z5x/2=(-1)^n*π/4+πnx=(-1)^n*π/2+2πn,n∈z63x=(-1)^n*π/4+πnx=(-1)^n*π/12+πn/3,n∈z7sin(x/3)=-√2 -1нет решения...