(m^2/m^2-4 - m+2/m-2): 4m+4/2-m - вопрос №622146422422442 от linochka1083 06.12.2020 05:17

Question

Алгебра: (m^2/m^2-4 - m+2/m-2): 4m+4/2-m ﻿

linochka1083 · Answer

(m^2/(m-2)(m+2)-m+2/m-2):4m+4/2-m=(m^2-m(m+2)(m-2)/(m+2)(m-2)+2/m-2):4m+4/2-m=(m^2-m(m^2-4)+2(m+2)/m^2-4):4m+4/2-m=2m+8/m^2-4:4m+4/2-m=2m+8/m^2-4*1/4m+4/2-m=2m+8/4m^3-16m+4/2-m=2(m+4)/4m(m^2-4)-4/m-2=m+4-4(m+2)/2m(m-2)(m+2)=1/2m-2...

(m^2/m^2-4 - m+2/m-2): 4m+4/2-m ﻿

(m^2/m^2-4 - m+2/m-2): 4m+4/2-m