Найдите корни уравнения 40+16х-2/х^2-5/х^3=0 - вопрос №6147328401622530 от sunnyAkhhhh 13.03.2022 06:00

Question

Алгебра: Найдите корни уравнения 40+16х-2/х^2-5/х^3=0

sunnyAkhhhh · Answer

40+16x-2/x²-5/x³=0  |×x³                        ОДЗ: х²≠0   х³≠0   х≠040x³+16x⁴-2x-5=016x⁴+40x³-2x-5=0x₁=0,516x⁴+40x³-2x-5   |_x-0,5_16x⁴-8x³                | 16x³+48x²+22x+10            48x³-2x            48x³-24x²                                 22x²-2x                     22x²-12x                                                    10x-5                               10x-5                                                                        016x³+48x²+22x+10=0x₂=-2,516x³+48x²+22x+10  |_x+2,5_16x³+40x²                 ...