Выражения (1+2m) (2m-1) -m (4m+5) = 2x(2x-y)^2 + (2x_y)^3= - вопрос №572817112214522223 от dmitriy14nagiev 19.05.2020 08:28

Question

Алгебра: Выражения (1+2m) (2m-1) -m (4m+5) = 2x(2x-y)^2 + (2x_y)^3=

dmitriy14nagiev · Answer

● (1+2m)×(2m-1) -m×(4m+5)= 4m^2 - 1 - 4m^2 -5m=(-1)-5m
● 2x(2x-y)^2 + (2x-y)^3= 2x(4x^2-4xy+y^2)+(8x^3 - 3×4x^2×y+3×2xy^2-y^3)= 8x^3 -8x^2×y+2xy^2+8x^3-12x^2×y+6xy^2-y^3= 16x^3 - 20x^2×y + 8xy^2 - y^3