1. 6cos^x +4 sin x cos x = 1 2.а) sin (x + п/3) - вопрос №557036416412332323 от FWEAAFE 10.11.2020 21:10

Question

Алгебра: 1. 6cos^x +4 sin x cos x = 1 2.а) sin (x + п/3) ≤ √3/2; б) cos ( 3x - 2п/3) ≥ - 1/2

FWEAAFE · Answer

2. а) sin(x+π/3)≤√3/2α₂=arcsin√3/2=π/3α₁=-π-arcsin√3/2=-π-π/3=-4π/3-4π/3+2πn≤x+π/3≤π/3+2πn | -π/3-5π/3+2πn≤x≤2πn, n∈Zб) cos(3x-2π/3)≥-1/2α₂=arccos(-1/2)=2π/3α₁=-arccos(-1/2)=-2π/3-2π/3+2πn≤3x-2π/3≤2π/3+2πn | +2π/32πn≤3x≤4π/3+2πn | ×1/32πn/3≤x≤4π/9+2πn/3   ...