log^2(3)1/27 =(log_3(1/27))^2 =[log_3(3^(-3))]^2 =[-3]^2 =9
log^2_3(1/27)
по определению логарифма 3^x=1/27 => x=-3
(-3)^2=9
log^2(3)1/27 =(log_3(1/27))^2 =[log_3(3^(-3))]^2 =[-3]^2 =9
log^2_3(1/27)
по определению логарифма 3^x=1/27 => x=-3
(-3)^2=9