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х•(х-2)•(х+1)=х2°(х-1)

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x (x - 2)(x + 1) = x2(x-1)

(x²+ 2x)(x + 1) = x2(x - 1)

(x²+ 2x)(x + 1) = 2x(x - 1)

x³+ x²+ 2x²+ 2x = 2x(x-1)

x³+ x²+ 2x²+ 2x = 2x²-2x

x³+ x²+ 2x = - 2x

x³+x²+2x + 2x = 0

x³+x²+ 4x = 0

x(x²+x + 4) = 0

x² + x + 4 = 0

x = 0