dx | | 2t dt dt
∫ = | замена:√x=t, x=t², dx=2t* dt | = ∫ =2∫ = 2 * ln|1+t|+C=
√x (1+√x) | | t (1+t) 1+t
=2 ln|1+√x|+C
dx | | 2t dt dt
∫ = | замена:√x=t, x=t², dx=2t* dt | = ∫ =2∫ = 2 * ln|1+t|+C=
√x (1+√x) | | t (1+t) 1+t
=2 ln|1+√x|+C