1/10((0-3)^2*1+(1-3)^2*2+(2-3)^2*1+(3-3)^2*1+(4-3)^2*2+(5-3)^2*3 - вопрос №9210880110032113222321332143225323 от sanyakuzmin01 11.07.2021 00:57

Question

Математика: 1/10((0-3)^2*1+(1-3)^2*2+(2-3)^2*1+(3-3)^2*1+(4-3)^2*2+(5-3)^2*3 в ответе получилось 3,2 объясните как

sanyakuzmin01 · Answer

(0-3)^2=(-3)^2=99*1=9(1-3)^2=(-2)^2=44*2=89+8=17(2-3)^2=-1^2=11*1=117+1=18(3-3)^2=0^2=00*1=018+0=18(4-3)^2=1^2=11*2=218+2=20(5-3)^2=2^2=44*3=1220+12=321/10*32=32:10=3.2...