Найди корень уравнения -4 2/3-y=-2 1/6

1)x^2/3 - 3 = 0
x^2/3 = 3
х^2 = 9
x1=3
x2= - 3
2)b1=3*2-1 = 6-1 = 5
b2 = 3*2^2 - 1 = 12-1 = 11
q=b2/b1 = 11/5
3)((a+1)/2a)/((a^2-1)/4a^2)) = (a+1)*4a^2/2a*(a^2-1) = (a+1)*2a/(a-1)(a+1) = 2a/a-1