Решете : 28х-10(х-2)+37 -40х+100=-(32+х)+7 -5х+2(х+2)=-7х-10 - вопрос №8674707281023740100327522710181826 от naziflashru 31.10.2020 13:46

Question

Математика: Решете : 28х-10(х-2)+37 -40х+100=-(32+х)+7 -5х+2(х+2)=-7х-10 -18х-(18+х)-2(х+6)+7 11х-(22х+100)=-2

naziflashru · Answer

28x-10(x-2)+37=028x-10x+20+37=018x=-57x=-57/18-40x+100=-(32+x)+7-40x+100=-32-x+7-39x=-125x=125/39-5x+2(x+2)=-7x-10-5x+2x+4=-7x-104x=-14x=-14/4-18x-(18+x)-2(x+6)+7=0-18x-18-x-2x-12+7=0-21x=23x=-23/2111x-(22x+100)=-211x-22x-100=-2-11x=98x=-98/11...