4целых 3/7: (6целых 2/15-8,2)+(49,75-27 целых 1/12)×3 - вопрос №77710244376215824975271123 от elizavetabobrova 18.01.2021 12:32

Question

Математика: 4целых 3/7: (6целых 2/15-8,2)+(49,75-27 целых 1/12)×3

elizavetabobrova · Answer

1) 6 2/15 - 8 1/5 = 6 2/15 - 8 3/15 = -2 1/15

2) 4 3/7 : (-2 1/15) = - 31/7 : 31/15 = - 31/7 * 15/31 = - 15/7 = -2 1/7

3) 49 3/4 - 27 1/12 = 49 9/12 - 27 1/12 = 22 8/12 = 22 2/3

4) 22 2/3 * 3 = 68/3 * 3 = 68

5) - 2 1/7 + 68 = 65 6/7

ответ: 65 целых 6/7