Y=sqrt ((x-5)/(x-1)) найти y (-1/3) - вопрос №76181945113 от 1234дмит232323 07.11.2021 16:26

Question

Математика: Y=sqrt ((x-5)/(x-1)) найти y (-1/3)

1234дмит232323 · Answer

Y=√((x-5)/(x-1))y = ( 1 / 2√((x-5)/(x-1)) )* ((x-5)/(x-1)) = (1 / 2) * √((x-1)/(x-5)) * ((x-5)/(x-1)) = A((x-5)/(x-1)) = ((x-5) * (x-1) - (x-5) * (x-1) ) / (x-1)^2 = (((x) -(5) ) * (x-1) - (x-5) * ((x) -(1) ) ) / (x-1)^2 = ((1-0) * (x-1) - (x-5) * (1-0) ) / (x-1)^2 = (1 * (x-1) - (x-5) * 1) / (x-1)^2 = (x-1 - x+5) / (x-1)^2 = (-1 +5) / (x-1)^2 = 4 / (x-1)^2f (-1/3) = 4 / (-1/3 - 1)^2 = 4 / (-1/3 - 3/3)^2 = 4 / (-4/3)^2 = 4 / (16/9) = (4*9)/16 =9/4...

Y=sqrt ((x-5)/(x-1)) найти y'(-1/3)