(7/16+5/12)*1целых7/41+1целых1/39: (4/13- 20/39) - вопрос №7382054716512174111394132039 от irina20042005 29.03.2023 13:35

Question

Математика: (7/16+5/12)*1целых7/41+1целых1/39: (4/13- 20/39) /-типо дробь

irina20042005 · Answer

(7/16+5/12)*1целых7/41+1целых1/39:(4/13- 20/39)=

1) 7/16+5/12= 21/48+20/48= 41/48
2) 41/48*1 7/41= 41/48*48/41= 1
3) 4/13-20/39= 12/39-20/39= -8/39
4) 1 1/39:(-8/39)=40/39:(-8/39)= 40/39*(-39/8)= -5
5) 1+(-5)= 1-5= -4