1) (1 3/28-25/42-5/14): 2 2/13+11/13: 1 7/26= - вопрос №68138571132825425142213111317262211221219281635 от bochtorovmaksim 27.02.2021 09:01

Question

Математика: 1) (1 3/28-25/42-5/14): 2 2/13+11/13: 1 7/26= 2) (2 1/12: 2 1/2+(1 9/28-16/35)*2 6/11-11/30=

bochtorovmaksim · Answer

1) (1 3/28-25/42-5/14):2 2/13+11/13:1 7/26= 1-25/42-5/14=-25/42-15/42=-40/42= -20/211 3/28-20/21=31/28-20/21=186/168-160/168=26/168=13/8413/84:2 2/13=13/84×28/13=1/311/13: 1 7/26=11/13×26/33=2/31/3+2/3=3/3=12) (2 1/12:2 1/2)+(1 9/28-16/35)*2 6/11-11/30=2 1/12:2 1/2=25/12×2/5=5/61 9/28-16/35=37/28-16/35=185/140-64/140=121/140121/140×2 6/11=121/140×28/11=11/55/6+11/5-11/30=25/30+66/30-11/30=80/30=2 20/30= 2 2/3...