1)2(х+3)+5(х+1)= 2)9(7+у)+8(6+у)= 3)4(3х+23)+7(6+5х)= - вопрос №6427259123512978634323765412983116 от dascha21schou 19.04.2023 19:12

Question

Математика: 1)2(х+3)+5(х+1)= 2)9(7+у)+8(6+у)= 3)4(3х+23)+7(6+5х)= 4)12(9+8у)+3(11+6у)= өрнекті ықшамда

dascha21schou · Answer

2(х+3)+5(х+1)=2х+6+5х+5=7х+119(7+у)+8(6+у)=63+9у+48+8у=17у+1114(3х+23)+7(6+5х)=12х+92+42+35х=47х+13412(9+8у)+3(11+6у)=108+96у+33+18у=114у+141...