34x-68=68; 54x-28=26; 2528: k-24=64; (x+59): 42=86; - вопрос №64009763468685428262528246459428665330321632 от livadin3105 16.03.2022 08:01

Question

Математика: 34x-68=68; 54x-28=26; 2528: k-24=64; (x+59): 42=86; 6x+5x-33=0; 3x-2x+16=32. прям щяс надо

livadin3105 · Answer

34x-68=68;34х = 68 + 6834х = 136х = 136 : 34х = 454x-28=26;54х = 26 + 2854х = 54х = 12528:k-24=64;2528:k = 24 + 642528:k = 88k = 2528 : 88k = 308 и 8/11(x+59):42=86;х + 59 = 86 * 42х + 59 = 3612х = 3612 - 59х = 35536x+5x-33=0;11х = 33х = 33x-2x+16=32. х = 32 - 16х = 16...