А)0,4*a^3*b^5*1.5*a^3*b; б) 0,45*m^3*n^2*p^4*10/9*m^8*n^11*p^6; - вопрос №6299802043515304532410981160332 от SpaniGar 22.11.2022 04:50

Question

Математика: А)0,4*a^3*b^5*1.5*a^3*b; б) 0,45*m^3*n^2*p^4*10/9*m^8*n^11*p^6; в)0,3*(a^3)^2*b^5*1.1*a*(b^2)^3; г)0,35*a^7*b^3*c^11*8/7*a*b^12*c^23

SpaniGar · Answer

а)0,4*a^3*b^5*1.5*a^3*b = 0,4*1,5 *а^(3+3)*b^(5+1)=0,6(ab)^6

б) 0,45*m^3*n^2*p^4*10/9*m^8*n^11*p^6 = (0,45*10/9)*(m^(3-8)*n^(2-11)* p^(4-6)) =0,5 / (m^5 * n^9 * p²)

в)0,3*(a^3)^2*b^5*1.1*a*(b^2)^3 = 0,3*1,1 * a^(6+1)*b^(5+6)= 0,33a^7b^11

г)0,35*a^7*b^3*c^11*8/7*a*b^12*c^23 = (0,35*8/7)*(a^(7-1)b^(3-12)c^(11-23))= 0,4a^6 / b^9c^12