1) (24-4y)*6,5-5,8=41 2)(10y-3,3): 5,2+8,9=10 - вопрос №5637426124465584121033528910 от DnoKaKtys 18.02.2020 09:41

Question

Математика: 1) (24-4y)*6,5-5,8=41 2)(10y-3,3): 5,2+8,9=10

DnoKaKtys · Answer

1) (24-4y)*6,5-5,8=41(24-4y)*6,5=41+5,8156-26y=46,826y=156-46,826y=109,2y=109,2:26y=4,22)(10y-3,3):5,2+8,9=10(10y-3,3):5,2=10-8,9(10y-3,3):5,2=1,110y-3,3=1,1*5,210y-3,3=5,7210y=5,72+3,310y=9,02y=9,02:10y=0,902...