1)х*(х=5)=(х+3)^2 2)х(х(х-1))+6=х(х+3)*(х-4) - вопрос №5242335153221634 от sksool0360figf 21.10.2020 23:57

Question

Математика: 1)х*(х=5)=(х+3)^2 2)х(х(х-1))+6=х(х+3)*(х-4)

sksool0360figf · Answer

1) х*(х+5)=(х+3)^2x^2 + 5x = x^2 + 6x +9 - x -9 = 0- x = 9x = -9 2) х(х(х-1))+6=х(х+3)*(х-4)x(x^2-x)) + 6 = х^2+3x*(х-4)x^3 - x2 +6 = x^3 - 4x^2 + 3x^2 -12xx^3 - x^3 - x^2 + 4x^2 - 3x^2 + 12x+6 = 012x + 6 = 012x = -6x = -0,5...