1)sin 2x =0,5 2)cos 2x =0,5 3)-3tgx=3 4)2ctgx=2 - вопрос №521754112052205333422 от gulnazira2005 07.01.2022 18:19

Question

Математика: 1)sin 2x =0,5 2)cos 2x =0,5 3)-3tgx=3 4)2ctgx=2

gulnazira2005 · Answer

1) sin2x=1/22x=(-1)arcsin1/2+Πn, n€Z2x=(-1)^n Π/6+Πn, n€Zx=(-1)^n Π/12+Πn/2, n€Z2) cos2x=1/21-2sin^2x=1/22sin^2x=1/2sin^2x=1/4sinx=+-1/2x1=(-1)^n arcsin1/2+Πn, n€Zx2=Π-(-1)^n arcsin1/2+Πn, n€Z3) -3tgx=3tgx=-1x=-Π/4+Πn, n€Z4) 2ctgx=2ctgx=1x=Π/4+Πn, n€Z...