1целая 1/3х + 0,2=1: 3/25y-1,2=0,6: 1,32x+4=10 целых - вопрос №4156304113021325120613241035 от fariii046 11.12.2022 18:38

Question

Математика: 1целая 1/3х + 0,2=1: 3/25y-1,2=0,6: 1,32x+4=10 целых 3/5

fariii046 · Answer

1)1 1/3х+0,2=11 1/3х=1-0,21 1/3х=0,8х=0,8:1 1/3х=8/10:4/3х=8/10*3/4х=3/52)3/25у-1,2=0,63/25у=0,6+1,23/25у=1,8у=1,8:3/25у=18/10:3/25у=18/10*25/3у=33)1,32х+4=10 3/51,32х=10 3/5-41,32х=6 3/5х=6 3/5: 1,32х=33/5:132/100х=33/5*100/132х=5...