(19.1/6+43,75)÷5/6÷(13,3-11,5)×1.2/3+(26,8-23.3/7)÷6/35÷0,5= - вопрос №39167841916437556133115123268233763505 от arujan20071 21.03.2022 15:26

Question

Математика: (19.1/6+43,75)÷5/6÷(13,3-11,5)×1.2/3+(26,8-23.3/7)÷6/35÷0,5=

arujan20071 · Answer

19 1/6+43,75=19 50/300+43 225/300=62 275/300=62 11/12
2)13,3-11,5=1,8
3)26,8-23 3/7=26 8/10-23 3/7=26 56/70-23 30/70=3 13/35
4)62 11/12:5/6=151/2=75 1/2
5)75 1/2:1,8=751/2:1 8/10=41 17/18
6)41 17/18*1 2/3=69 4954
7)3 13/35:6/35=19 2/3
8)19 2/3:0,5=19 2/3:5/10=39 1/3
9)69 4954+39 1/3=69 49/54+39 18/54 =108 67/54=109 13/54