36×(5а+19)=30а+1134 725t-123t-292=912 (c-3)×12=20-4×(c+2) - вопрос №3792778365193011347251232929123122042 от jeon200 15.10.2020 15:32

Question

Математика: 36×(5а+19)=30а+1134 725t-123t-292=912 (c-3)×12=20-4×(c+2)

jeon200 · Answer

36×(5а+19)=30а+1134180а + 684 = 30 а + 1134150а = 450а = 450÷150 а = 3725t-123t-292=912725t-123t = 912+292602t = 1204t= 1204÷602t = 2(c-3)×12=20-4×(c+2)12c -36= 20 - 4c -812c +4c = 20 -8 +3616c = 48c = 48÷16c = 3...