1)log2 56+2 log2 12-log2 63 2)log3 1/27 3)log4(2x+3)=3 - вопрос №34644381256221226323127342334532 от girina210482 28.06.2020 13:43

Question

Математика: 1)log2 56+2 log2 12-log2 63 2)log3 1/27 3)log4(2x+3)=3 4)log5(x-3) 2

girina210482 · Answer

1) log2 (56*12^2/63)=log2 128 = 7 2) log3 1 - log3 27=0-3= -33) log4 (2x+3) = log4 642x+3=642x=61x=30,54) log5(x-3) log5 25x-3 25x 22...

1)log2 56+2 log2 12-log2 63 2)log3 1/27 3)log4(2x+3)=3 4)log5(x-3)< 2