1вариант 1) cosx = 1/2 3) tgx = 1 4) cos(x+п/3) - вопрос №33588171112314305216307 от minecraftak2015 09.12.2022 09:12

Question

Математика: 1вариант 1) cosx = 1/2 3) tgx = 1 4) cos(x+п/3) = 0 5) 2cosx = 1 6) 3tgx = 0 7) sin4x = 1

minecraftak2015 · Answer

1. +-π/3+πk, k∈z,2. π/4+πk, k∈z,3. x+π/3=π/2+πk, k∈z,x=π/2-π/3+πk, k∈z,x=π/6+πk, k∈z,4. cosx=1/2,x=+-π/3+πk, k∈z,5. tgx=0,x=πk, k∈z,6.4x=π/2+2πk, k∈z,x=π/8+(1/2π)k, k∈z...