Log4(4x+2)=2 log1/3(x^2=8x)= -2 4^x 1/4 log2(8-4x) - вопрос №31326654422132824142841835 от strelchyksofia20005 09.01.2020 00:13

Question

Математика: Log4(4x+2)=2 log1/3(x^2=8x)= -2 4^x 1/4 log2(8-4x) lgx=lg18 - lg3 +lg5 - lg15

strelchyksofia20005 · Answer

Log4(4x+2)=24x+2=4²4x=16-24x=14x=14/4=7/2=3.5log1/3(x^2-8x)= -2x²-8x=(1/3)^-2x²-8x=9x²-8x-9=0D=16+9=25x(1)=4+5=9x(2)=4-5=-14^x 1/44^x 4^ -1x -1lgx=lg18 - lg3 +lg5 - lg15lgx=lg(18+5)/3+15x=23/18...

Log4(4x+2)=2 log1/3(x^2=8x)= -2 4^x< 1/4 log2(8-4x) lgx=lg18 - lg3 +lg5 - lg15