Даны векторы а(0; 4; -7) и b(7; -9; 1) найти 3a-2b и -a+4b

3a-2b = 3*(0,4,-7) - 2*(7,-9,1)=(0,12,-21)-(14,-18,2) = (-14,30,-23)
-a+4b = (0,-4,7) + (28,-36,4) = (28,-40,11)

3*(0,4,-7) – 2*(7,-9,1)= (0,12,-21)-(14,-18,2)= (0-14,12+18,-21-2)= (-14, 30,-23)
-(0,4,-7) +4*(7,-9,1)= (0,-4,7) + (28,-36,4)= (0+28,-4-36,-7+4)= (28, -40,11)