(1/3+1/3+1/3++1/3-1/2-1/2-1//2)*(1/100+1/100+1/100++1/100) - вопрос №2050419131313131212121100110011001100108 от stanvadrem 04.01.2020 11:30

Question

Математика: (1/3+1/3+1/3++1/3-1/2-1/2-1//2)*(1/100+1/100+1/100++1/100) ( 10 раз ) ( 8 раз ) ( 15 раз )

stanvadrem · Answer

=(1/3(1+1+...+1)-1/2(1+1+...+1))•1/100(1+1...+1)=(1/3•10-1/2•8)•1/100•15=(10/3-8/2)•15/100=(3 1/3-4)•3/20=(-2/3)•3/20=-1/10=-0,1...