1)1/2+1/3(13/4+5/6*1/8)= 2)5/3*4/6+(8/6-5/3)= 3)2/4-1/2(3/8+6/7*1/5= - вопрос №204465511213134561825346865332412386715 от dianakazaryan1 06.10.2022 12:10

Question

Математика: 1)1/2+1/3(13/4+5/6*1/8)= 2)5/3*4/6+(8/6-5/3)= 3)2/4-1/2(3/8+6/7*1/5= решите !

dianakazaryan1 · Answer

1)1/2+1/3(13/4+5/6*1/8)=
5/6 * 1/8 = 5/48
13/4 + 5/48 = 156/48 + 5/48 = 161/48
1/3 * 161/48 = 161/44
1/2 + 161/144 = 72/144 +161/144 = 233/144 = 1 89/144

2)5/3*4/6+(8/6-5/3)=
8/6 -5/3 = 8/6 -10/6 = - 2/6
5/3 * 4/6 = 20/18 = 10/9
10/9 + ( - 2/6) = 20/18 -6/18 = 14/18 = 7/9

3)2/4-1/2(3/8+6/7*1/5= решаю как если скобка после 1/5
6/7 * 1/5 = 6/35
3/8 +6/35 = 105/280 +48/280 = 153/280
1/2 * 153/280 = 153/560
2/4 - 153/560 = 280/560 -153/560 = 127/560

1)1/2+1/3(13/4+5/6*1/8)= 2)5/3*4/6+(8/6-5/3)= 3)2/4-1/2(3/8+6/7*1/5= решите !

1)1/2+1/3(13/4+5/6*1/8)= 2)5/3*4/6+(8/6-5/3)= 3)2/4-1/2(3/8+6/7*1/5= решите !