1. (4+5 целых 1/6)*(32/3-13/33) 2. 6 целых 5/12*4/11-11 - вопрос №204113014516323133326512411111419323 от Yuliaburtseva1 12.03.2021 06:35

Question

Математика: 1. (4+5 целых 1/6)*(32/3-13/33) 2. 6 целых 5/12*4/11-11 целых 1/4*1/9 3. (2/3x-4/5)*15=8

Yuliaburtseva1 · Answer

(9 1/6)*(32*11-13)/33 = 55/6*(352 - 13)/33 = 5/6*339/3 = 5/6*113 = 565/6
(6 5/12)*4/11 - (11 1/4)*1/9 = 77/12*4/11 - 45/4*1/9 = 7/3 - 5/4 = (7*4-3*5)/(3*4) = 13/12
(2/3*x - 4/5)*15 = 8
2*x/3 - 4/5 = 8/15
(2*x*5 - 4*3)/(3*5) = 8/15
10x - 12 = 8
x = 2