Решите показательное уравнение 16^х-4^x+1=32​

16^x - 4^(x + 1) = 32

4^2x - 4*4^x = 32

4^x = y > 0

y^2 - 4y - 32 = 0

D = 16 + 128 = 144

y12 = (4 +- 12)/2 = 8  - 4

y1 = -4 нет < 0

y2 = 8

4^x = 8

log(4) 4^x = log(4) 8

x = log(4) 8 = log(2^2) 2^3 = 3/2