1) 1-sinl cosl tg l ; sinl=0,7 2) 2 sin l /2 ctg - вопрос №188507011072222233 от ArianTop 15.05.2023 12:05

Question

Математика: 1) 1-sinl cosl tg l ; sinl=0,7 2) 2 sin l /2 ctg l /2 - cos l /2 3) cos l=⅗ ; 3п

ArianTop · Answer

1-sinL*cosL*sinL/cosL=1-sinL*sinL=1-0,7*0,7=1-0,49=0,51       2sinL/2*cosL/2/sinL/2-cosL/2=2cosL/2-cosL/2=cosL/2                                                        ...