Вариант №2 1) 3(x-3) = 4x+
2)4(x-3) = x+ 3;
3) 2(x- 3) = -3
4) (x+3)4 = (x - 9)
5) 2x-5 = 8 - 3*
6) 5x/3 = (2 -
7) (5x+7)/8 - (3x
8) (5x -1)/3 - (6x
9) (3х - 2)/4 + (2
10) (2x - 4)/5 +

Question

Математика: Вариант №2 1) 3(x-3) = 4x+ 2)4(x-3) = x+ 3; 3) 2*(x- 3) = -3* 4) (x+3)*4 = (x - 9) * 5) 2x-5 = 8 - 3* 6) 5x/3 = (2 - 7) (5x+7)/8 - (3x 8) (5x -1)/3 - (6x 9) (3х - 2)/4 + (2 10) (2x - 4)/5 +

Tupiccc · Answer

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