1,2×(5-а)= (m -4x)×(-6)=2,5×(4x-6y-2)=-0,1×(100a+10b - вопрос №1391525612546254620110010 от larikhambekov 26.09.2020 04:47

Question

Математика: 1,2×(5-а)= (m -4x)×(-6)=2,5×(4x-6y-2)=-0,1×(100a+10b​

larikhambekov · Answer

1,2•(5-а)=1,2•5-1,2=6-1,2а(m-4x)•(-6)=-6m-4x•(-6)=-6m+4x•6=6m+24x2,5×(4x-6y-2)=2,5•4x-2,5•6y-2,5•2=10x-15y-2,5•2=10x-15y-5-0,1×(100a+10b)=0,1•100a+0,1•10b=10a+0,1•10b=10a+b...

1,2×(5-а)= (m -4x)×(-6)=2,5×(4x-6y-2)=-0,1×(100a+10b​

1,2×(5-а)=
(m -4x)×(-6)=
2,5×(4x-6y-2)=
-0,1×(100a+10b