Відомо масову частку w(c)=84,21% , mr(h)=15,79 , d(пов.)=3,93. знайти алкан

б:

D(alk)(29) = 3.93 ==> M(alk) = 3.93 * 29 = 114 г/моль

CnH2n+2 = 114

14n = 112

n = 112/14 = 8.

C8H18 — октан

б:

D(alk)(29) = 3.93 ==> M(alk) = 3.93 * 29 = 114 г/моль

n(C) = (84.21*114)/1200 = 8
n(H) = (15.79*114)/100 = 18

C8H18 — октан.