Составить схему электролиза водного раствора na2s с угольным анодом. ,нужно подробное решение

                                                               Na2S

                                                           (раствор)

                                                               /      \

                                                   2Na(+)  +   S(2-)

катод:                                                                                анод:

2H2O+2e=H2+2OH(-)                                                              S(2-) -2e=S(0)

                                                2H2O+2e=H2+2OH(-)  -1восстановление;окислитель

                                                 S(2-) -2e= S(0)              -1окисление;восстановитель.

                                             2H2O+S(2-) = H2+2OH(-) +S(0)

                                             2H2O+S(2-) +2Na(+) = H2+2OH(-) +2Na(+) +S(0)

                                             2H2O+Na2S(электролиз) =H2+2NaOH+S