Two perpendicular forces act on a 400 g object. The object moves with an
acceleration, a=25 m/s?. If F,=8 N find the other
force?

(c) With a1= 0, x = (1/2)a1t2 + vit becomes x = vt or x =15m/s(35s) = 530m.

(d) a2 = (Vf - Vi) / t ; a2 = [25m/s - 15m/s]/8.0s = 1.25 m/s2.

(e) ΣF=Ma; Fe-Ff =Ma2; Fe-1800N =2400kg(1.25m/s2); Fe=1800N+3000N = 4800N.

Объяснение:

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