Осуществить превращения по генетическим цепочкам: X1—H2O, Hg2+→ (CH3)2CO —H2, K→ X2 → (CH3)2CHBr —KOH, спирт, → X3 →X4

Решение:
CH3– C = CH —H2O, Hg2+→ (CH3)2CO —H2, K→ (CH3)2CH– OH─ +HBr→ (CH3)2CHBr —KOH(спирт)→ →CH3– CH = CH2─t, K→ CH3– C = CH

1. CH3– C = CH + H2O ─ Hg2+→ (CH3)2CO
2. (CH3)2CO + H2 ─K→ (CH3)2CH– OH
3. (CH3)2CH– OH+ HBr → (CH3)2CHBr
4. (CH3)2CHBr + KOH(спиртовый) → CH3– CH = CH2 + KBr + H2O
5. CH3– CH = CH2─t, K→ CH3– C = CH + H2