After a certain period of time after the start of the reaction equation which СО2(g) + С(s) = 2СО(s), concentration of carbon oxide is reduced

given:
(С₁(СО₂))/(С₂(СО₂))=4
find:
(υ₁)/(υ₂)- ?
Solution:
υ₁ =kС_1^2 (СО₂)
С₂(СО₂) =(С₁(СО₂))/4
υ₂=k•С_1^2 (СО₂)  = k⁡〖〖•((С₁(СО₂))/4)〗^2 〗=k•(kС_1^2 (СО₂))/16
(υ₁)/(υ₂)= k•С_1^2 (СО₂) ∶ k•(kС_1^2 (СО₂))/16=16
Answer:  the reaction rate decreases 16 times .