(a+1)(a-1)(a2-a+1)(a2+a+1)(a6+1)(a12+1)(a24+1) - вопрос №978443511212161121241 от поля1209348756 27.04.2022 00:46

Question

Алгебра: (a+1)(a-1)(a2-a+1)(a2+a+1)(a6+1)(a12+1)(a24+1) выражение

поля1209348756 · Answer

вот ваше решение: [tex](a+1)(a-1)(a2-1+1)(a2+1+1)(a6+1)(a12+1)(a24+1)=\= (a^{2} -1)(a+1)(3a+1)(6a+1)(12a+1)(24a+1) =\= (a^{3}+a^{2}-a-1)(3a+1)(6a+1)(12a+1)(24a+1) =\= (3a^{4}+a^{3}+3a^{3} +a^{2} -3a^{2} -a-3a-1)(6a+1)(12a+1)(24a+1) =\= (3a^{4}+4a^{3}-2a^{2} -4a-1)(6a+1)(12a+1)(24a+1) =\= (18a^{5}+3a^{4}+24a^{4}+4a^{3}-12a^{3}-2a^{2} -24a^{2}+4a-6a-1)(12a+1)(24a+1) = \= (18a^{5}+27a^{4}-8a^{3}-26a^{2}-10a-1)(12a+1)(24a+1) =\=(216a^{6} +18a^{5}+324a^{5}+27a^{4}-96a^{4}-8a^{3}-312a^{3}-26a^{2}-120a^{2}...