Выразите log24 132 через a и b если log12 6=a, - вопрос №9194885241321261211 от bajkovat7 23.02.2023 03:31

Question

Алгебра: Выразите log24 132 через a и b если log12 6=a, log12 11=b

bajkovat7 · Answer

Log24(132) = log12(132) / log12(24) = log12(12*11) / log12(144/6) =

= ( log12(12) + log12(11) ) / ( log12(144) - log12(6) ) =

= ( 1 + b ) / ( log12(12^2) - a ) = ( 1 + b ) / ( 2 log12(12) - a ) =

= ( 1 + b ) / ( 2 - a )